Question

question 17 1 pts what is the ion that results from the following process where e⁻ represents an electron (gain of 3 electrons): $_7^{14}x + 3e^-\to?$ $si^{3 -}$ $o^{2 -}$ $n^{3 -}$ $mg^{3 -}$ question 18 1 pts what is the ion that results from the following process where e⁻ represents an electron (loss of 2 electrons): $_{20}^{40}x\to? + 2e^-$ $mg^{2 +}$ $na^+$ $al^{3 +}$ $ca^{2 +}$

Explanation:

Step1: Identify the element in Question 17

The atomic number of the element in $\ce{_{7}^{14}X}$ is 7, which is nitrogen (N). When it gains 3 electrons, it forms an anion with a - 3 charge, $\ce{N^{3 - }}$.

Step2: Identify the element in Question 18

The atomic number of the element in $\ce{_{20}^{40}X}$ is 20, which is calcium (Ca). When it loses 2 electrons, it forms a cation with a + 2 charge, $\ce{Ca^{2+}}$.

Answer:

Question 17: C. $\ce{N^{3 - }}$
Question 18: D. $\ce{Ca^{2+}}$