Question

question 18
4 pts
a nugget of gold with a mass of 521 g is added to 50.0 ml of water. the water level rises to a volume of 77.0 ml. what is the density of the gold?
19.3 g/ml
6.77 g/ml
1.00 g/ml
10.4 g/ml

Explanation:

Step1: Calculate volume of gold

The volume of gold is equal to the final volume of water - the initial volume of water. So, $V = 77.0\ mL - 50.0\ mL=27.0\ mL$.

Step2: Calculate density of gold

The density formula is $
ho=\frac{m}{V}$, where $m = 521\ g$ and $V = 27.0\ mL$. Then $
ho=\frac{521\ g}{27.0\ mL}\approx19.3\ g/mL$.

Answer:

19.3 g/mL