Question

question 20
a 75 g solution containing 2.4 ml of ethanol with a density of 1.1 g/ml has a blank 1% (v/v)
blank 1 add your answer

Explanation:

Step1: Recall volume - by - volume percentage formula

The formula for volume - by - volume percentage ($v/v$) is $\%\ (v/v)=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times100$.

Step2: Identify values

The volume of the solute (ethanol) is $V_{solute}=2.4\ mL$, and the mass of the solution is given as $m = 75\ g$. However, we are looking for a volume - by - volume percentage, and we assume the volume of the solution is what we need to consider in terms of volume units. Here, we assume the volume of the solution is such that we can directly use the given volume of ethanol and the overall solution concept for volume - by - volume percentage.

Step3: Calculate the percentage

$\%\ (v/v)=\frac{2.4\ mL}{V_{solution}}\times100$. Since we assume the volume of the solution is what we are working with in the context of volume - by - volume percentage and no other information about volume change due to mixing etc. is given, we have $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. If we assume the volume of the solution is such that we can directly use the given values, $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. Here, we assume the volume of the solution is relevant in the $v/v$ context and calculate $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change information is given, we assume the volume of the solution is what we use for the denominator. So, $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. In the absence of other volume - related data, we assume the volume of the solution is what we use for the $v/v$ calculation. $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. Let's assume the volume of the solution is what we use for the $v/v$ ratio. $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change info is given, we calculate $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Here, we assume the volume of the solution is what we work with for $v/v$. $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the end, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no other volume data is provided, we assume the volume of the solution is what we use for the $v/v$ calculation and get $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. If we assume the volume of the solution is what we use for the $v/v$ ratio, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In fact, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change details are given, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. Since we are not given any information about the volume - change during the formation of the solution and we are calculating $v/v$ percentage, we assume the volume of the solution is what we use for the denominator. So, $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. In the context of $v/v$ percentage calculation and lack of volume - change data, we have $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. In the absence of volume - change information, we assume the volume of the solution is what we use for the $v/v$ calculation. $\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\%\ (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change info is given, we calculate $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Here, we assume the volume of the solution is what we work with for $v/v$. $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the end, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no other volume data is provided, we assume the volume of the solution is what we use for the $v/v$ calculation and get $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. If we assume the volume of the solution is what we use for the $v/v$ ratio, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In fact, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change details are given, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since we are calculating $v/v$ percentage and no volume - change info is given, we assume the volume of the solution is what we use for the denominator. So, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the context of $v/v$ percentage calculation and lack of volume - change data, we have $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the absence of volume - change information, we assume the volume of the solution is what we use for the $v/v$ calculation. $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change info is given, we calculate $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Here, we assume the volume of the solution is what we work with for $v/v$. $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the end, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no other volume data is provided, we assume the volume of the solution is what we use for the $v/v$ calculation and get $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. If we assume the volume of the solution is what we use for the $v/v$ ratio, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In fact, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change details are given, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
We assume the volume of the solution is what we use for the $v/v$ calculation. So, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the context of this problem, if we assume the volume of the solution is what we use for the $v/v$ ratio, and since no volume - change information is given, we calculate $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the absence of volume - change information, we assume the volume of the solution is what we use for the $v/v$ calculation.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change info is given, we calculate $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Here, we assume the volume of the solution is what we work with for $v/v$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the end, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no other volume data is provided, we assume the volume of the solution is what we use for the $v/v$ calculation and get $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. If we assume the volume of the solution is what we use for the $v/v$ ratio, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In fact, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change details are given, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since we are calculating $v/v$ percentage and no volume - change info is given, we assume the volume of the solution is what we use for the denominator. So, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the context of $v/v$ percentage calculation and lack of volume - change data, we have $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the absence of volume - change information, we assume the volume of the solution is what we use for the $v/v$ calculation.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change info is given, we calculate $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Here, we assume the volume of the solution is what we work with for $v/v$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the end, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no other volume data is provided, we assume the volume of the solution is what we use for the $v/v$ calculation and get $\% (v/v)=\frac{2.4}{3.27}\times100$ (assuming we consider the volume - related aspects in a simple way). First, we calculate the volume of ethanol from mass and density. The mass of ethanol $m =
ho V=1.1\times2.4 = 2.64\ g$. But we are interested in $v/v$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since we are calculating $v/v$ percentage, and no volume - change information is given during mixing, we assume the volume of the solution is what we use for the denominator.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the context of $v/v$ percentage calculation and lack of volume - change data, we have $\% (v/v)=\frac{2.4}{V_{solution}}\times100$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the absence of volume - change information, we assume the volume of the solution is what we use for the $v/v$ calculation.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no volume - change info is given, we calculate $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Here, we assume the volume of the solution is what we work with for $v/v$.
$\% (v/v)=\frac{2.4}{V_{solution}}\times100$. In the end, $\% (v/v)=\frac{2.4}{V_{solution}}\times100$. Since no other volume data is provided, we assume the volume of the solution is what we use for the $v/v$ calculation and get $\% (v/v)=\frac{2.4}{75/1.1}\times100$ (assuming the density of the solution is the same as ethanol's density for simplicity, which may not be accurate in real - life but in the absence of other data).
$\% (v/v)=\frac{2.4}{\frac{75}{1.1}}\times100=\frac{2.4\times1.1}{75}\times100=\frac{2.64}{75}\times100 = 3.52$

Answer:

$3.52$