Question

question 35 of 60
how many total valence electrons are in the $\text{cse}_2$ lewis structure?
$\bigcirc$ 16
$\bigcirc$ 10
$\bigcirc$ 12
$\bigcirc$ 4
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Explanation:

Step1: Find valence electrons of each atom

Carbon (C): 4 valence electrons; Selenium (Se): 6 valence electrons each.

Step2: Calculate total valence electrons

Total = Valence electrons of C + 2×Valence electrons of Se
$\text{Total} = 4 + 2\times6 = 4 + 12 = 16$

Answer:

16