Question

question 4
aluminum has a density of 2.70 g/cm³. what volume is occupied by a block of aluminum which weighs 4.32 kg?
(a) 0.000625 cm³
(b) 0.625 cm³
(c) 1.60 cm³
(d) 1.60 l
question 5

Explanation:

Step1: Convert mass to grams

Since $1\ kg = 1000\ g$, a $4.32\ kg$ block of aluminum has a mass $m = 4.32\times1000=4320\ g$.

Step2: Use density - mass - volume formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. Rearranging for volume gives $V = \frac{m}{
ho}$. Given $
ho = 2.70\ g/cm^{3}$ and $m = 4320\ g$, then $V=\frac{4320\ g}{2.70\ g/cm^{3}} = 1600\ cm^{3}=1.60\ L$ (since $1\ L=1000\ cm^{3}$).

Answer:

D. 1.60 L