Question

question # 6 by krystal wellmann
in the boron simulation, if there are 7 atoms of boron-11 and 2 atoms of boron-10 in a sample, what is the percent abundance of boron-11? (round your answer to the closest whole number)
70%
88%
78%
22%

Explanation:

Step1: Find total number of atoms

Total atoms = Atoms of boron - 11 + Atoms of boron - 10 = \(7 + 2 = 9\)

Step2: Calculate percent abundance of boron - 11

Percent abundance = \(\frac{\text{Atoms of boron - 11}}{\text{Total atoms}} \times 100\%\) = \(\frac{7}{9} \times 100\% \approx 77.78\%\)

Step3: Round to closest whole number

Rounding \(77.78\%\) gives \(78\%\)

Answer:

78%