Question

question 5 (2 points)
what is the anion in the formula - al₂(so₃)₃?
there is no anion.
so₃⁻
so₃²⁻
so₃
so₃³⁻

Explanation:

To determine the anion in \( \text{Al}_2(\text{SO}_3)_3 \), we analyze the ionic compound. Aluminum (\( \text{Al} \)) typically has a \( +3 \) charge (\( \text{Al}^{3+} \)). In the formula, there are 2 \( \text{Al}^{3+} \) ions, so the total positive charge is \( 2\times(+3) = +6 \). The compound is neutral, so the total negative charge from the anions must be \( -6 \). There are 3 of the anion, so each anion must have a charge of \( \frac{-6}{3} = -2 \). Thus, the anion is \( \text{SO}_3^{2-} \) (sulfite ion).

Answer:

\( \text{SO}_3^{2-} \) (the option with "SO₃²⁻")