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QUESTION IMAGE

rank the elements or compounds in the table below in decreasing order o…

Question

rank the elements or compounds in the table below in decreasing order of their boiling points. that is, choose 1 next to the substance with the highest boiling point, choose 2 next to the substance with the next highest boiling point, and so on.
substance | chemical symbol, formula or lewis structure | boiling point
a | h—o—o—h | select
b | hgcl₂ | 4 (lowest)
c | hcl | select
d | h₂ | select

Explanation:

To rank the substances by boiling point, we analyze the intermolecular forces (IMFs):

Step 1: Identify Substances and IMFs

  • Substance A (H₂O₂): Contains hydrogen bonding (H bonded to O) and dipole-dipole, plus London dispersion forces (LDF).
  • Substance B (HgCl₂): Ionic compound (Hg²⁺ and Cl⁻), so ionic bonds (strongest IMFs for these options).
  • Substance C (HCl): Polar molecule, dipole-dipole forces + LDF.
  • Substance D (H₂): Nonpolar, only LDF (weakest IMFs).

Step 2: Relate IMFs to Boiling Point

Boiling point depends on IMF strength:

  • Ionic bonds (HgCl₂) > Hydrogen bonding (H₂O₂) > Dipole-dipole (HCl) > LDF (H₂).

Step 3: Rank in Decreasing Order

  1. Highest Boiling Point: HgCl₂ (ionic, strongest IMFs) – but wait, wait! Wait, H₂O₂ has H-bonding, but HgCl₂ is ionic. Wait, no—wait, HgCl₂ is actually a covalent compound (mercury(II) chloride, molecular), but with significant polarity. Wait, correction: H₂O₂ has hydrogen bonding (strong), HgCl₂ is a polar molecule (dipole-dipole + LDF, but molar mass ~271 g/mol), HCl (molar mass ~36.5 g/mol, dipole-dipole), H₂ (molar mass 2 g/mol, LDF).

Wait, re-evaluating:

  • H₂O₂: H-bonding (strong), molar mass ~34 g/mol.
  • HgCl₂: Polar, molar mass ~271 g/mol (LDF increases with molar mass).
  • HCl: Polar, molar mass ~36.5 g/mol.
  • H₂: Nonpolar, molar mass 2 g/mol.

IMF strength hierarchy: H-bonding (H₂O₂) > Dipole-dipole (HgCl₂, HCl) + LDF (with HgCl₂ having much larger molar mass, so stronger LDF than HCl).

So correct order (decreasing boiling point):

  1. H₂O₂ (A) – H-bonding + LDF (molar mass 34)
  2. HgCl₂ (B) – Dipole-dipole + LDF (molar mass 271, strong LDF)
  3. HCl (C) – Dipole-dipole + LDF (molar mass 36.5)
  4. H₂ (D) – LDF (molar mass 2)

Wait, initial mistake: HgCl₂ is molecular (covalent), not ionic. So H-bonding in H₂O₂ is stronger than dipole-dipole in HgCl₂, but HgCl₂ has much higher molar mass, so LDF dominates? Wait, no—H-bonding is stronger than dipole-dipole + LDF for similar molar masses, but HgCl₂ is much heavier. Let’s check actual boiling points:

  • H₂O₂: ~150 °C (decomposes, but boiling point ~150)
  • HgCl₂: ~302 °C
  • HCl: -85 °C
  • H₂: -253 °C

Ah! So HgCl₂ has a higher boiling point than H₂O₂. So the correct order (decreasing boiling point) is:

  1. HgCl₂ (B) – ~302 °C
  2. H₂O₂ (A) – ~150 °C
  3. HCl (C) – -85 °C
  4. H₂ (D) – -253 °C

So the ranking is:

  • Highest (1): HgCl₂ (B)
  • Next (2): H₂O₂ (A)
  • Next (3): HCl (C)
  • Lowest (4): H₂ (D) (already marked as 4)

Answer:

  1. B. HgCl₂
  2. A. H₂O₂ (Lewis structure H-O-O-H)
  3. C. HCl
  4. D. H₂ (already set as 4)

(For the dropdowns: Highest boiling point is B (HgCl₂), next is A (H₂O₂), then C (HCl), then D (H₂).)