Question

1. a rectangular - shaped piece of wood has a length of 10.71 cm, a width of 5 cm, and a height of 3 cm. after using an electronic balance, the piece of wood weighs 96.4 grams. what is the density of the piece of wood in the units grams per milliliters?
2. what are the conditions at stp?

Explanation:

Step1: Calculate the volume of the rectangular - shaped wood

The volume formula for a rectangular prism is $V = l\times w\times h$. Given $l = 10.71$ cm, $w = 5$ cm, and $h = 3$ cm. So $V=10.71\times5\times3=160.65$ $cm^{3}$. Since $1$ $cm^{3}=1$ mL, the volume $V = 160.65$ mL.

Step2: Calculate the density

The density formula is $
ho=\frac{m}{V}$, where $m = 96.4$ grams and $V = 160.65$ mL. So $
ho=\frac{96.4}{160.65}\approx0.60$ g/mL.

for sub - question 9:
STP stands for Standard Temperature and Pressure. The standard temperature is $T = 273$ K ($0^{\circ}C$) and the standard pressure is $P = 1$ atm.

Answer:

The density of the piece of wood is approximately $0.60$ g/mL.