Question

to rent a certain meeting room, a college charges a reservation fee of $16 and an additional fee of $6 per hour. the chemistry club wants to spend at most $58 on renting the room. what are the possible numbers of hours the chemistry club could rent the meeting room? use $r$ for the number of hours. write your answer as an inequality solved for $r$.

Explanation:

Step1: Set up the inequality

The total cost is the reservation fee plus the per - hour fee times the number of hours. The reservation fee is $16$ and the per - hour fee is $6$ per hour. The club wants to spend at most $58$. So the inequality is $16 + 6r\leq58$.

Step2: Subtract 16 from both sides

To isolate the term with $r$, we subtract 16 from both sides of the inequality: $16+6r - 16\leq58 - 16$, which simplifies to $6r\leq42$.

Step3: Divide both sides by 6

Dividing both sides of the inequality $6r\leq42$ by 6 gives $r\leq7$.

Answer:

$r\leq7$