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7. | | °c | °f | k | | room temperature | 25 | 77 | 298.15 | | ice wate…

Question

7.

°c°fk
room temperature2577298.15
ice water032273.15
boiling water100212373.15
  1. how well do your thermometer readings agree with the accepted values for the freezing point and boiling point of water? express any discrepancy as a deviation in degrees. (5 pts.)

Explanation:

Step 1: Recall Accepted Values

The accepted freezing point of water is \( 0^\circ \text{C} \) (or \( 32^\circ \text{F} \), \( 273.15 \text{ K} \)) and the accepted boiling point of water is \( 100^\circ \text{C} \) (or \( 212^\circ \text{F} \), \( 373.15 \text{ K} \)).

Step 2: Analyze Freezing Point (Ice Water)

  • For \( ^\circ \text{C} \): Measured is \( 0^\circ \text{C} \), accepted is \( 0^\circ \text{C} \). Deviation \( = |0 - 0| = 0^\circ \text{C} \).
  • For \( ^\circ \text{F} \): Measured is \( 32^\circ \text{F} \), accepted is \( 32^\circ \text{F} \). Deviation \( = |32 - 32| = 0^\circ \text{F} \).
  • For \( \text{K} \): Measured is \( 273.15 \text{ K} \), accepted is \( 273.15 \text{ K} \). Deviation \( = |273.15 - 273.15| = 0 \text{ K} \).

Step 3: Analyze Boiling Point (Boiling Water)

  • For \( ^\circ \text{C} \): Measured is \( 100^\circ \text{C} \) (wait, the table has "10 0" which is likely a typo for 100), accepted is \( 100^\circ \text{C} \). Deviation \( = |100 - 100| = 0^\circ \text{C} \).
  • For \( ^\circ \text{F} \): Measured is \( 212^\circ \text{F} \), accepted is \( 212^\circ \text{F} \). Deviation \( = |212 - 212| = 0^\circ \text{F} \).
  • For \( \text{K} \): Measured is \( 373.15 \text{ K} \), accepted is \( 373.15 \text{ K} \). Deviation \( = |373.15 - 373.15| = 0 \text{ K} \).

Step 4: Analyze Room Temperature (Optional, but for completeness)

Room temperature is typically around \( 25^\circ \text{C} \) (accepted), so measured \( 25^\circ \text{C} \) matches. \( 77^\circ \text{F} \) (since \( F = \frac{9}{5}C + 32 = \frac{9}{5}(25) + 32 = 77 \)), so deviation \( 0^\circ \text{F} \). \( 298.15 \text{ K} \) (since \( K = C + 273.15 = 25 + 273.15 = 298.15 \)), deviation \( 0 \text{ K} \).

Answer:

For the freezing point (ice water), the thermometer readings match the accepted values (deviation \( 0^\circ \text{C} \), \( 0^\circ \text{F} \), \( 0 \text{ K} \)). For the boiling point (boiling water), the thermometer readings also match the accepted values (deviation \( 0^\circ \text{C} \), \( 0^\circ \text{F} \), \( 0 \text{ K} \)). Room temperature readings also match the typical accepted value with no deviation.