QUESTION IMAGE
Question
- a sample of copper with a mass of 63.5 g contains 6.02 x 10^{23} atoms. calculate the mass of a single copper atom. show your work and include correct units.
Step1: Identify the given values
We are given that mass of sample $m = 63.5$ g and number of atoms $N=6.02\times 10^{23}$.
Step2: Use the formula for mass of one - atom
The mass of a single atom $m_{atom}=\frac{m}{N}$.
Substitute $m = 63.5$ g and $N = 6.02\times 10^{23}$ into the formula:
$m_{atom}=\frac{63.5\ g}{6.02\times 10^{23}}$
$m_{atom}\approx1.055\times 10^{-22}$ g
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$1.055\times 10^{-22}$ g