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for silicon (14, silicon, 28.086): atomic # = 14 mass number = ____ # o…

Question

for silicon (14, silicon, 28.086):
atomic # = 14
mass number = ____

of protons = 14

of neutrons = 14

of electrons = 14

for b (5, b, 10.81):
atomic # = 5
mass number = ____

of protons = 5

of neutrons = 6

of electrons = 5

for bromine (35, bromine, 79.904):
atomic # = 35
mass number = ____

of protons = 35

of neutrons = 45

of electrons = 35

other sections (partial):

of protons = 8

of neutrons = 8

of electrons = 8

of protons = 30

of neutrons = 35

of electrons = 30

of protons = 3

of neutrons = 4

of electrons = 3

Explanation:

Step1: Recall mass number formula

Mass number = # of Protons + # of Neutrons

Step2: Calculate Silicon's mass number

$\text{Mass number (Si)} = 14 + 14 = 28$

Step3: Calculate Boron's mass number

$\text{Mass number (B)} = 5 + 6 = 11$

Step4: Calculate Bromine's mass number

$\text{Mass number (Br)} = 35 + 45 = 80$

Step5: Identify element names

  • Top right: 8 protons = Oxygen (O)
  • Middle right: 30 protons = Zinc (Zn)
  • Bottom right: 3 protons = Lithium (Li)

Answer:

Top Right (Oxygen):

of Protons = 8

of Neutrons = 8

of Electrons = 8

Middle Right (Zinc):

of Protons = 30

of Neutrons = 35

of Electrons = 30

Bottom Right (Lithium):

of Protons = 3

of Neutrons = 4

of Electrons = 3

Silicon:

Mass number = 28

Boron:

Mass number = 11
Element name: Boron

Bromine:

Mass number = 80