QUESTION IMAGE
Question
- the specific heat capacity of copper is 3.900 j/g°c. the specific heat capacity of aluminum is 8.9 j/g°c. choose the correct statement below.
a. it takes more energy to increase the temperature of aluminum than copper
b. aluminum has a lower heat capacity than copper
c. it takes less energy to increase the temperature of aluminum than copper
d. copper has a higher heat capacity than aluminum
- calorimetry is
a. a type of exercise
b. the process of measuring the amount of heat released or absorbed during a chemical reaction
c. the process of measuring the temperature of water
d. the study of food calories
- we can measure the amount of thermal energy that is transferred in a system using the formula q = mcδt.
q: the amount of thermal energy transferred
m: the mass of the object or substance
c: the specific heat of the object or substance
δt: the change in temperature that occurs
in a calorimetry experiment, you combusted an entire chocolate - chip muffin under a soda can that contained water.
→ the can contained 100g of water
→ the specific heat of water is 4.186 j/g°c
→ the change in temperature of the water was 20°c
→ assume there was no error in the experiment and all of the energy in the muffin was transferred to the water in the can.
how much energy in joules was in the muffin? use q = mcδt and show your work.
Step1: Identify values
$m = 100g$, $c=4.186\ J/g^{\circ}C$, assume $\Delta T = 10^{\circ}C$ (not given in problem, assuming a reasonable value for illustration, if no other value is provided in - context. If a specific $\Delta T$ value is given later, this step can be adjusted).
Step2: Apply formula
$Q=mc\Delta T=(100g)\times(4.186\ J/g^{\circ}C)\times(10^{\circ}C)$
$Q = 4186\ J$
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$4186\ J$ (Note: The actual answer depends on the correct value of $\Delta T$. If $\Delta T$ is different, recalculate using the formula $Q = mc\Delta T$ with the appropriate $\Delta T$ value)