Question

specify the number of protons (#p⁺), neutrons (#n⁰) and electrons (#e⁻) given the following symbol:
₃₀⁶⁴zn
#p+
choose
choose
30
34
94
28
#n0
#e-

Explanation:

Step1: Identify proton number

The sub - script in the isotope notation represents the atomic number (Z), which is equal to the number of protons. For $_{30}^{64}Zn$, the atomic number is 30, so the number of protons $\#p^+=30$.

Step2: Calculate neutron number

The mass number (A) is the sum of protons and neutrons. Here, $A = 64$ and $Z=30$. Using the formula $A=Z + \#n^0$, we can find the number of neutrons: $\#n^0=A - Z=64 - 30=34$.

Step3: Determine electron number

For a neutral atom, the number of electrons is equal to the number of protons. Since zinc is neutral here, $\#e^- = 30$.

Answer:

$\#p^+=30$
$\#n^0 = 34$
$\#e^-=30$