Question

step 1: name the type of chemical reaction

1. ex: synthesis

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step 2: balance the following chemical equations:
— n₂ + — h₂ → — nh₃
— kclo₃ → — kcl + — o₂
— nacl + — f₂ → — naf + — cl₂
— h₂ + — o₂ → — h₂o
— agno₃ + — mgcl₂ → — agcl + — mg(no₃)₂
— albr₃ + — k₂so₄ → — kbr + — al₂(so₄)₃
— ch₄ + — o₂ → — co₂ + — h₂o
— c₃h₈ + — o₂ → — co₂ + — h₂o
— fecl₃ + — naoh → — fe(oh)₃ + — nacl
— p + — o₂ → — p₂o₅
— na + — h₂o → — naoh + — h₂
— ag₂o → — ag + — o₂
— co₂ + — h₂o → — c₆h₁₂o₆ + — o₂
— k + — mgbr₂ → — kbr + — mg
— hno₃(aq) + — ba(oh)₂(aq) → — ba(no₃)₂(aq) + — h₂o (l)
— c₅h₁₂(g) + — o₂(g) → — co₂(g) + — h₂o(g)
— al(s) + — fe₂o₃(aq) → — al₂o₃(aq) + — fe(s)
— al(s) + — o₂(g) → — al₂o₃ (s)

Explanation:

Step1: Balance nitrogen in $N_2 + H_2

ightarrow NH_3$
Set coefficient of $N_2$ as 1, coefficient of $NH_3$ as 2 to balance nitrogen: $N_2 + H_2
ightarrow 2NH_3$

Step2: Balance hydrogen

Set coefficient of $H_2$ as 3 to balance hydrogen: $N_2+3H_2 = 2NH_3$

Step3: Balance oxygen in $KClO_3

ightarrow KCl + O_2$
Find least - common multiple of 2 and 3 for oxygen atoms. Set coefficient of $KClO_3$ as 2 and coefficient of $O_2$ as 3: $2KClO_3
ightarrow KCl + 3O_2$

Step4: Balance potassium and chlorine

Set coefficient of $KCl$ as 2: $2KClO_3=2KCl + 3O_2$

Step5: Balance halogens in $NaCl+F_2

ightarrow NaF + Cl_2$
Set coefficient of $NaCl$ as 2 and coefficient of $NaF$ as 2: $2NaCl+F_2 = 2NaF+Cl_2$

Step6: Balance hydrogen and oxygen in $H_2 + O_2

ightarrow H_2O$
Set coefficient of $H_2O$ as 2 to balance oxygen, then coefficient of $H_2$ as 2: $2H_2+O_2 = 2H_2O$

Step7: Balance silver and chlorine in $AgNO_3+MgCl_2

ightarrow AgCl + Mg(NO_3)_2$
Set coefficient of $AgNO_3$ as 2 and coefficient of $AgCl$ as 2: $2AgNO_3+MgCl_2 = 2AgCl+Mg(NO_3)_2$

Step8: Balance aluminum and sulfate in $AlBr_3+K_2SO_4

ightarrow KBr + Al_2(SO_4)_3$
Set coefficient of $AlBr_3$ as 2 and coefficient of $K_2SO_4$ as 3, then coefficient of $KBr$ as 6: $2AlBr_3 + 3K_2SO_4=6KBr+Al_2(SO_4)_3$

Step9: Balance carbon and hydrogen in $CH_4+O_2

ightarrow CO_2 + H_2O$
Set coefficient of $H_2O$ as 2 to balance hydrogen, then coefficient of $O_2$ as 2: $CH_4+2O_2 = CO_2+2H_2O$

Step10: Balance carbon, hydrogen and oxygen in $C_3H_8+O_2

ightarrow CO_2 + H_2O$
Set coefficient of $CO_2$ as 3 and coefficient of $H_2O$ as 4 to balance carbon and hydrogen, then coefficient of $O_2$ as 5: $C_3H_8+5O_2 = 3CO_2+4H_2O$

Step11: Balance iron, chlorine, sodium and oxygen in $FeCl_3+NaOH

ightarrow Fe(OH)_3+NaCl$
Set coefficient of $NaOH$ as 3 and coefficient of $NaCl$ as 3: $FeCl_3+3NaOH = Fe(OH)_3+3NaCl$

Step12: Balance phosphorus and oxygen in $P + O_2

ightarrow P_2O_5$
Set coefficient of $P$ as 2 and coefficient of $O_2$ as $\frac{5}{2}$, then multiply all coefficients by 2: $4P + 5O_2=2P_2O_5$

Step13: Balance sodium, hydrogen and oxygen in $Na + H_2O

ightarrow NaOH + H_2$
Set coefficient of $Na$ as 2, coefficient of $H_2O$ as 2, coefficient of $NaOH$ as 2: $2Na + 2H_2O=2NaOH+H_2$

Step14: Balance silver and oxygen in $Ag_2O

ightarrow Ag + O_2$
Set coefficient of $Ag_2O$ as 2, coefficient of $Ag$ as 4, coefficient of $O_2$ as 1: $2Ag_2O = 4Ag+O_2$

Step15: Balance carbon, hydrogen and oxygen in $CO_2+H_2O

ightarrow C_6H_{12}O_6+O_2$
Set coefficient of $CO_2$ as 6 and coefficient of $H_2O$ as 6, coefficient of $O_2$ as 6: $6CO_2+6H_2O = C_6H_{12}O_6+6O_2$

Step16: Balance potassium, magnesium and bromine in $K + MgBr_2

ightarrow KBr+Mg$
Set coefficient of $K$ as 2 and coefficient of $KBr$ as 2: $2K + MgBr_2=2KBr+Mg$

Step17: Balance hydrogen, nitrogen, barium and oxygen in $HNO_3+Ba(OH)_2

ightarrow Ba(NO_3)_2+H_2O$
Set coefficient of $HNO_3$ as 2 and coefficient of $H_2O$ as 2: $2HNO_3+Ba(OH)_2 = Ba(NO_3)_2+2H_2O$

Step18: Balance carbon, hydrogen and oxygen in $C_5H_{12}+O_2

ightarrow CO_2 + H_2O$
Set coefficient of $CO_2$ as 5 and coefficient of $H_2O$ as 6, coefficient of $O_2$ as 8: $C_5H_{12}+8O_2 = 5CO_2+6H_2O$

Step19: Balance aluminum and iron in $Al + Fe_2O_3

ightarrow Al_2O_3+Fe$
Set coefficient of $Al$ as 2 and coefficient of $Fe$ as 2: $2Al+Fe_2O_3 = Al_2O_3+2Fe$

Step20: Balance aluminum and oxygen in $Al+O_2

ightarrow Al_2O_3$
Set coefficient of $Al$ as 4 and coefficient of $O_2$ as 3: $4Al + 3O_2=2Al_2O_3$

Answer:

1. $N_2+3H_2 = 2NH_3$
2. $2KClO_3=2KCl + 3O_2$
3. $2NaCl+F_2 = 2NaF+Cl_2$
4. $2H_2+O_2 = 2H_2O$
5. $2AgNO_3+MgCl_2 = 2AgCl+Mg(NO_3)_2$
6. $2AlBr_3 + 3K_2SO_4=6KBr+Al_2(SO_4)_3$
7. $CH_4+2O_2 = CO_2+2H_2O$
8. $C_3H_8+5O_2 = 3CO_2+4H_2O$
9. $FeCl_3+3NaOH = Fe(OH)_3+3NaCl$
10. $4P + 5O_2=2P_2O_5$
11. $2Na + 2H_2O=2NaOH+H_2$
12. $2Ag_2O = 4Ag+O_2$
13. $6CO_2+6H_2O = C_6H_{12}O_6+6O_2$
14. $2K + MgBr_2=2KBr+Mg$
15. $2HNO_3+Ba(OH)_2 = Ba(NO_3)_2+2H_2O$
16. $C_5H_{12}+8O_2 = 5CO_2+6H_2O$
17. $2Al+Fe_2O_3 = Al_2O_3+2Fe$
18. $4Al + 3O_2=2Al_2O_3$