Question

treatment of the nitrogen with h₂ gas resulted in 1.251 g nh₃. how many moles of nitrogen are present? ? mol n hint: get the nitrogen out of the nh₃, just like you took the c out of co₂ and h out of h₂o. do not round! include lots of digits in your answer since this is part of a larger calculation.

Explanation:

Step1: Calculate moles of \(NH_3\)

Molar mass of \(NH_3\) is \(14.0067 + 3\times1.00794 = 17.03052\space g/mol\). Moles of \(NH_3=\frac{1.251\space g}{17.03052\space g/mol}\).
\[n_{NH_3}=\frac{1.251}{17.03052}\approx0.073456\space mol\]

Step2: Moles of N in \(NH_3\)

1 mole of \(NH_3\) has 1 mole of N. So moles of N = moles of \(NH_3\).
\[n_N = 0.073456\space mol\]

Answer:

\(0.073456\) (or more precise value from the calculation \(\frac{1.251}{17.03052}\))