Question

types of reactions, balancing, and lcm quiz
1 fill in the blank 2 points
bonus: balance the chemical equation
type your answer... c₃h₇oh + type your answer... o₂ → type your answer... co₂ + type your answer... h₂o

Explanation:

Step1: Count initial atoms

Reactants: $C_5H_7OH$ has 5 C, 8 H, 1 O; $O_2$ has 2 O. Products: $CO_2$ has 1 C, 2 O; $H_2O$ has 2 H, 1 O.

Step2: Balance C atoms

Assign coefficient 5 to $CO_2$ to match 5 C on left.

$$\_\_C_5H_7OH + \_\_O_2 ightarrow 5CO_2 + \_\_H_2O$$

Step3: Balance H atoms

Assign coefficient 4 to $H_2O$ to match 8 H on left.

$$\_\_C_5H_7OH + \_\_O_2 ightarrow 5CO_2 + 4H_2O$$

Step4: Balance O atoms

Calculate total O on right: $5\times2 + 4\times1 = 14$. Subtract 1 O from $C_5H_7OH$, so $O_2$ needs $\frac{13}{2}$.

$$1C_5H_7OH + \frac{13}{2}O_2 ightarrow 5CO_2 + 4H_2O$$

Step5: Eliminate fraction

Multiply all coefficients by 2.

$$2C_5H_7OH + 13O_2 ightarrow 10CO_2 + 8H_2O$$

Step6: Verify atom counts

Reactants: 10 C, 16 H, 28 O. Products: 10 C, 16 H, 28 O. Balanced.

Answer:

2, 13, 10, 8