Question

use the activity series below to predict the products of each of the following reactions. you do not need to balance the equations. li > k > ba > sr > ca > na > mg > al > mn > zn > cr > fe > cd > co > ni > sn > pb > h > sb > bi > cu > ag > pd > hg > pt > au f₂ > cl₂ > br₂ > i₂ ccl₄ + br₂ →? no reaction brcl + c cbr₄ + cl₂

Explanation:

Step1: Analyze the activity series for halogens

The activity series for halogens is \( \text{F}_2 > \text{Cl}_2 > \text{Br}_2 > \text{I}_2 \). This means that a more reactive halogen can displace a less reactive halogen from its compound. Here, we are looking at the reaction between \( \text{CCl}_4 \) (where \( \text{Cl} \) is the halogen in the compound) and \( \text{Br}_2 \) (the halogen trying to displace).

Step2: Compare the reactivity of Cl₂ and Br₂

From the halogen activity series, \( \text{Cl}_2 \) is more reactive than \( \text{Br}_2 \) (since \( \text{Cl}_2 \) comes before \( \text{Br}_2 \) in the series \( \text{F}_2 > \text{Cl}_2 > \text{Br}_2 > \text{I}_2 \)). For a displacement reaction to occur, the halogen doing the displacing ( \( \text{Br}_2 \) here) must be more reactive than the halogen in the compound ( \( \text{Cl} \) in \( \text{CCl}_4 \) ). Since \( \text{Br}_2 \) is less reactive than \( \text{Cl}_2 \), it cannot displace \( \text{Cl} \) from \( \text{CCl}_4 \).

Answer:

no reaction