Question

use the activity series below to predict the products of each of the following reactions. you do not need to balance the equations. li > k > ba > sr > ca > na > mg > al > mn > zn > cr > fe > cd > co > ni > sn > pb > h > sb > bi > cu > ag > pd > hg > pt > au na₂co₃ + k →? no reaction k₂co₃ + na nak + co₃

Explanation:

To determine the reaction, we use the activity series. In a single - displacement reaction, a more reactive metal can displace a less reactive metal from its compound. From the activity series, we see that \(K\) is more reactive than \(Na\) (since \(K>Na\) in the series). So, \(K\) can displace \(Na\) from \(Na_2CO_3\). The reaction would be \(Na_2CO_3 + K
ightarrow K_2CO_3+Na\). The option "no reaction" is incorrect because \(K\) is more reactive than \(Na\), and the option "NaK + \(CO_3\)" is incorrect as the correct products are \(K_2CO_3\) and \(Na\) based on the displacement of \(Na\) by the more reactive \(K\).

Answer:

B. \(K_2CO_3 + Na\) (assuming the second option is labeled as B, if the original options had labels like A, B, C with A being "no reaction", B being \(K_2CO_3 + Na\) and C being \(NaK + CO_3\))