Question

using the mass and volume information, calculate the density of each object and answer the question below using the metal density reference chart.
seain, a high school student, measures the mass of a solid metal object. it has a mass of 350.0 grams. the student also measures the volume of that object and the object has a volume of 129.6 ml.
a) what is the density of the metal object?
2.701 g/ml
b) what metal could this object be made of?
aluminum
350.0 g / 129.6 ml = 2.701 g/ml
1 joan, another student, measures the mass of a solid metal object. it has a mass of 102.0 g. she also measures the volume of that object and the object has a volume of 9.027 ml.
a) what is the density of the metal object?
b) what could it be made of?
2 bart finds a solid shiny object and he hopes it is made of gold! it has a mass of 110.0 g and it has a volume of 10.0 ml.
a) what is the density of the metal object?
b) could the object be made of gold?
3 bart finds another shiny object! it has a mass of 124 g and a volume of 6.42 ml
a) what is the density of the metal object?
b) could the object be made of gold?
4 a student measures the mass of a solid metal object. it has a mass of 250.2 g. the student also measures the volume of that object and the object has a volume of 31.79 ml.
a) what is the density of the metal object?
b) what could this object be made of?
density of metals
solids (at 25 °c) | density (g/ml)
aluminum | 2.70
copper | 8.93
silver | 10.5
lead | 11.3
gold | 19.3
iron | 7.87
(c) bethany lau

Explanation:

Problem 1 (Joan's Object)

Part (a)

Step1: Recall density formula

Density ($
ho$) is calculated as mass ($m$) divided by volume ($V$), so $
ho = \frac{m}{V}$.

Step2: Substitute values

Given $m = 102.0\ \text{g}$ and $V = 9.027\ \text{mL}$, we calculate $
ho = \frac{102.0}{9.027}$.

Step3: Perform division

$\frac{102.0}{9.027} \approx 11.3\ \text{g/mL}$ (rounded appropriately).

We compare the calculated density (11.3 g/mL) with the density of metals in the chart. Lead has a density of 11.3 g/mL, so the object could be made of lead.

Step1: Use density formula

$
ho = \frac{m}{V}$, where $m = 110.0\ \text{g}$ and $V = 10.0\ \text{mL}$.

Step2: Substitute and calculate

$
ho = \frac{110.0}{10.0} = 11.0\ \text{g/mL}$

Answer:

$11.3\ \text{g/mL}$

Part (b)