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Question
5 what, if anything, is wrong with the nuclear equation shown below? (_{74}^{179}w+\frac{0}{ - 1}e
ightarrow\frac{179}{75}re) the daughter product has the wrong atomic number. the daughter product has the wrong mass number. the particle labeled \e\ should have an mass number of 1. there is nothing wrong with the equation.
Step1: Check mass - number conservation
In a nuclear equation, the sum of mass - numbers on the left - hand side must equal the mass - number on the right - hand side. The mass - number of \(^{179}_{74}W\) is 179 and the mass - number of the electron \(\ce{^0_{ - 1}e}\) is 0. So the sum of mass - numbers on the left is \(179 + 0=179\), and the mass - number of the product \(^{179}_{75}Re\) is 179. Mass - number is conserved.
Step2: Check atomic - number conservation
The sum of atomic numbers on the left - hand side must equal the atomic number on the right - hand side. The atomic number of \(^{179}_{74}W\) is 74 and the atomic number of the electron \(\ce{^0_{ - 1}e}\) is - 1. So the sum of atomic numbers on the left is \(74+( - 1)=73\), but the atomic number of the product \(^{179}_{75}Re\) is 75. Atomic number is not conserved, and the daughter product has the wrong atomic number.
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The daughter product has the wrong atomic number.