Question

1. what is the density for a powder that weighs 40.0 g and when added to 30.0 ml of water, the total volume is 45.0 ml?

1. mike’s pet turtle has a mass of 150.0 g. the turtle displaces 30.0 ml of water. calculate the density of the turtle.

1. given these values: \t\t1. 80.0 g has volume of 20.0 ml \t\t2. 4.00 cm³ has a mass of 12.0 g.

a) which substances has the greatest density?
b) are a and b more or less dense than water?

1. what is the density of iron if 100.0 g is added to 25.0 ml of water and the volume increases to 37.0 ml?

1. a beaker weighs 85.0 g empty and 104.0 g when filled with oil. it has a mass of 140.0 g when filled with water. find the density of the oil.

Explanation:

Problem 4

Step1: Find the volume of the powder

The volume of the powder is the total volume minus the volume of water. So, \( V = 45.0\space mL - 30.0\space mL = 15.0\space mL \)

Step2: Calculate density using \(

ho=\frac{m}{V} \)
Given \( m = 40.0\space g \) and \( V = 15.0\space mL \), then \(
ho=\frac{40.0\space g}{15.0\space mL}\approx2.67\space g/mL \)

Step1: Recall density formula \(

ho=\frac{m}{V} \)
Given \( m = 150.0\space g \) and \( V = 30.0\space mL \) (since volume displaced is the volume of the turtle)

Step2: Substitute values

\(
ho=\frac{150.0\space g}{30.0\space mL} = 5\space g/mL \)

Step1: Calculate density of substance 1 (let's say A)

Using \(
ho=\frac{m}{V} \), for \( m = 80.0\space g \), \( V = 20.0\space mL \), \(
ho_A=\frac{80.0\space g}{20.0\space mL}=4\space g/mL \)

Step2: Calculate density of substance 2 (let's say B)

For \( m = 12.0\space g \), \( V = 4.00\space cm^3 = 4.00\space mL \) (since \( 1\space cm^3 = 1\space mL \)), \(
ho_B=\frac{12.0\space g}{4.00\space mL}=3\space g/mL \)

Step3: Compare densities

Since \( 4\space g/mL>3\space g/mL \), substance A (80.0 g with volume 20.0 mL) has the greatest density.

Answer:

\( \approx2.67\space g/mL \)

Problem 5 (already has a solution, verifying)