Question

what element has an electron configuration of kr 5s² 4d¹⁰ 5p³?
bi
p
sb
i

Explanation:

Step1: Determine the atomic number of Kr

Krypton (Kr) has an atomic number of 36.

Step2: Calculate the total number of electrons from the given configuration

The given electron - configuration is $[Kr]5s^{2}4d^{10}5p^{3}$. The electrons from $[Kr]$ is 36. The number of electrons in $5s^{2}$ is 2, in $4d^{10}$ is 10 and in $5p^{3}$ is 3. So the total number of electrons $n=36 + 2+10 + 3=51$.

Step3: Identify the element based on atomic number

The element with an atomic number of 51 is Antimony, which has the symbol Sb.

Answer:

C. Sb