Question

what is the final chemical equation from the following intermediate chemical equations? p₄o₆(s) + p₄(s) → p₄(s) + 3o₂(g) p₄(s) + 5o₂(g) → p₄o₁₀(s)

Explanation:

Step1: Add the two given equations

First equation: $P_4(s)+3O_2(g)
ightarrow P_4O_6(s)$
Second equation: $P_4(s)+5O_2(g)
ightarrow P_4O_{10}(s)$
When we add them, we consider the reactants and products on both sides.

Step2: Combine like - terms

On the reactant side, we have $2P_4(s)+8O_2(g)$. On the product side, we have $P_4O_6(s)+P_4O_{10}(s)$. So the combined equation is $2P_4(s)+8O_2(g)
ightarrow P_4O_6(s)+P_4O_{10}(s)$

Answer:

$2P_4(s)+8O_2(g)
ightarrow P_4O_6(s)+P_4O_{10}(s)$