Question

what is the oxidation number for n in the compound nh₃? (recall that h usually has an oxidation number of +1 )
-3
-1
0
+3

Explanation:

Step1: Recall oxidation number rules

In a neutral compound, the sum of oxidation numbers is 0. Let the oxidation number of N be \( x \), and H has an oxidation number of +1. In \( NH_3 \), there are 3 H atoms.

Step2: Set up the equation

The sum of oxidation numbers in \( NH_3 \) is \( x + 3\times(+1)=0 \).

Step3: Solve for \( x \)

Simplify the equation: \( x + 3 = 0 \), so \( x = - 3 \).

Answer:

The oxidation number of N in \( NH_3 \) is -3, so the correct option is the one with -3 (the first option: -3).