Question

what is the ratio of aluminum cations to chloride anions in a sample of aluminum chloride?
1:1
1:3
2:1
3:1
question 8
1 pts
how many atoms are represented by one formula unit of aluminum sulfite, al₂(so₃)₃?
14
3
18
12

Explanation:

Step1: Determine aluminum chloride formula

Aluminum has a +3 charge ($Al^{3 + }$) and chloride has a - 1 charge ($Cl^{-}$). The chemical formula of aluminum chloride is $AlCl_{3}$.

Step2: Find ion - ratio

In $AlCl_{3}$, there is 1 aluminum cation ($Al^{3 + }$) and 3 chloride anions ($Cl^{-}$), so the ratio of aluminum cations to chloride anions is 1:3.

Step3: Analyze aluminum sulfite formula

The formula of aluminum sulfite is $Al_{2}(SO_{3})_{3}$.

Step4: Calculate number of atoms

For aluminum ($Al$), there are 2 atoms. For sulfur ($S$), since there are 3 sulfate ($SO_{3}$) groups and 1 sulfur in each, there are 3 sulfur atoms. For oxygen ($O$), with 3 sulfate groups and 3 oxygen atoms in each, there are $3\times3 = 9$ oxygen atoms. In total, $2 + 3+9=14$ atoms.

Answer:

Question 1: B. 1:3
Question 2: A. 14