Question

what is the total number of atoms on the reactant side of the chemical equation below? p₄o₁₀ + h₂o → h₃po₄

Explanation:

Step1: Analyze atoms in $P_4O_{10}$

In $P_4O_{10}$, there are 4 P - atoms and 10 O - atoms. So the number of atoms in $P_4O_{10}$ is $4 + 10=14$.

Step2: Analyze atoms in $H_2O$

In $H_2O$, there are 2 H - atoms and 1 O - atom.

Step3: Balance the chemical equation

The balanced equation is $P_4O_{10}+6H_2O
ightarrow4H_3PO_4$. On the reactant side, for $P_4O_{10}$ we have 14 atoms, and for 6 moles of $H_2O$, the number of H - atoms is $6\times2 = 12$ and the number of O - atoms is $6\times1=6$.

Step4: Calculate total atoms on reactant side

The total number of atoms on the reactant side is $14+12 + 6=32$.

Answer:

32