Question

what is the total number of phosphorus atoms on the right - hand side of this chemical equation? p₄(s)+4naoh(aq)+2h₂o(l)→2ph₃(g)+2na₂hpo₃(aq)

Explanation:

Step1: Analyze first product

In the product $2PH_3$, the coefficient of the compound is 2 and there is 1 phosphorus atom per molecule of $PH_3$. So the number of phosphorus atoms from $2PH_3$ is $2\times1 = 2$.

Step2: Analyze second product

In the product $2Na_2HPO_3$, the coefficient of the compound is 2 and there is 1 phosphorus atom per molecule of $Na_2HPO_3$. So the number of phosphorus atoms from $2Na_2HPO_3$ is $2\times1=2$.

Step3: Calculate total

Add the number of phosphorus atoms from both products. $2 + 2=4$.

Answer:

4