Question

which of the following is a balanced equation representing the reaction of acetone, c3h6o? c3h6o ---> co2 + h2o c3h6o ---> c3h6 + o2 2c3h6o ---> 6c + 6h2 + o2 c3h6o ---> ch2 + o question 19 which are the product(s) of this chemical reaction? alcl3 + 3nh4oh --> 3nh4cl + 3aloh al(oh)3 + 3nh4cl 3nh4al + cl3oh 3alcl3 + nh4oh

Explanation:

Step1: Recall balancing chemical equations

For the combustion of acetone ($C_3H_6O$), the general reaction is with oxygen to produce carbon - dioxide and water. The balanced equation for the complete combustion of acetone is $C_3H_6O + 4O_2
ightarrow3CO_2 + 3H_2O$. But we can check atom - by - atom balance for each option.
For the reaction $AlCl_3+3NH_4OH$, it is a double - displacement reaction. In a double - displacement reaction, the cations and anions of the reactants switch places.

Step2: Analyze the reaction of $AlCl_3$ and $3NH_4OH$

The aluminum ion ($Al^{3 + }$) combines with the hydroxide ion ($OH^-$) to form $Al(OH)_3$, and the ammonium ion ($NH_4^+$) combines with the chloride ion ($Cl^-$) to form $NH_4Cl$. The balanced chemical equation is $AlCl_3 + 3NH_4OH=Al(OH)_3+3NH_4Cl$.

Step3: Analyze acetone decomposition options

• Option $C_3H_6O

ightarrow CO_2 + H_2O$: Unbalanced. Left - hand side has 3 C atoms, while right - hand side has 1 C atom.

• Option $C_3H_6O

ightarrow C_3H_6+O_2$: Unbalanced. Left - hand side has 1 O atom, while right - hand side has 2 O atoms.

• Option $2C_3H_6O

ightarrow6C + 6H_2+O_2$: Balanced in terms of C, H, and O atoms.

• Option $C_3H_6O

ightarrow CH_2+O$: Unbalanced. Left - hand side has 3 C atoms, while right - hand side has 1 C atom.

Answer:

For the acetone decomposition question: $2C_3H_6O
ightarrow6C + 6H_2+O_2$
For the $AlCl_3 + 3NH_4OH$ reaction question: $Al(OH)_3 + 3NH_4Cl$