Question

which of these is the correct balanced chemical equation, including states of matter, for the reaction of aqueous solutions of strontium chloride and potassium sulfate? srcl₂(aq) + k₂so₄(aq) → srso₄(aq) + kcl(s) srcl₂(aq) + k₂so₄(aq) → srk₂(aq) + clso₄(aq) srcl₂(aq) + k₂so₄(aq) → srso₄(aq) + 2kcl(aq) srcl₂(aq) + k₂so₄(aq) → srso₄(s) + 2kcl(aq)

Explanation:

1. First, identify the reaction type: This is a double - displacement reaction. The general form is \(AB + CD

ightarrow AD+CB\). For the reaction between \(SrCl_{2}(aq)\) (strontium chloride) and \(K_{2}SO_{4}(aq)\) (potassium sulfate), the cations are \(Sr^{2 + }\) and \(K^{+}\), and the anions are \(Cl^{-}\) and \(SO_{4}^{2 - }\).

1. Then, determine the products: The products should be strontium sulfate (\(SrSO_{4}\)) and potassium chloride (\(KCl\)).
2. Next, check the solubility: Strontium sulfate (\(SrSO_{4}\)) is insoluble in water, so its state is solid (\(s\)). Potassium chloride (\(KCl\)) is soluble in water, so its state is aqueous (\(aq\)).
3. Now, balance the equation:

• On the left - hand side, we have 1 \(Sr\) atom, 2 \(Cl\) atoms, 2 \(K\) atoms, 1 \(S\) atom, and 4 \(O\) atoms.
• On the right - hand side, for the correct product combination (\(SrSO_{4}(s)\) and \(KCl(aq)\)):
• In \(SrSO_{4}\), we have 1 \(Sr\), 1 \(S\), and 4 \(O\). In \(KCl\), to balance the \(K\) and \(Cl\) atoms (since we have 2 \(K\) and 2 \(Cl\) on the left), we need 2 moles of \(KCl\). So the balanced equation is \(SrCl_{2}(aq)+K_{2}SO_{4}(aq)

ightarrow SrSO_{4}(s)+2KCl(aq)\).

• Let's analyze the other options:
• Option 1: \(KCl\) is shown as a liquid (\(l\)), which is incorrect as \(KCl\) is aqueous. Also, the balancing is wrong.
• Option 2: The product formulas are incorrect. The correct products should be \(SrSO_{4}\) and \(KCl\), not \(SrK_{2}\) and \(ClSO_{4}\).
• Option 3: \(SrSO_{4}\) is shown as aqueous, but \(SrSO_{4}\) is insoluble, so its state should be solid.

Answer:

D. \(SrCl_{2}(aq)+K_{2}SO_{4}(aq)
ightarrow SrSO_{4}(s)+2KCl(aq)\) (assuming the last option is D, if the options are labeled as A, B, C, D with the last one being this equation)