Question

wintergreen oil is produced in the following scheme from 6.84g of ch₃oh: c₇h₆o₃ + ch₃oh → c₈h₈o₃ + h₂o. if 12.5g of c₈h₈o₃ are actually produced and the reaction proceeds to 38.5% yield, what is the theoretical yield, in grams? 4.81g 9.63g 32.5g 64.9g. 10 numeric 10 points. 1.50 g of nitrogen monoxide react with 2.00 g of oxygen gas to produce nitrogen trioxide according to equation 1. equation 1. no (g) + o₂ (g) → no₃ (g). after all of the no has reacted, the excess o₂ is then reacted with 1.00 g of br₂ to produce bromine monoxide according to equation 2. equation 2. o₂ (g) + br₂ (l) → 2 bro (l). calculate how many grams of bro will be produced.

Explanation:

Step1: Recall the percent - yield formula

Percent yield = $\frac{\text{Actual yield}}{\text{Theoretical yield}}\times100\%$. We need to solve for the theoretical yield. Rearranging the formula gives Theoretical yield = $\frac{\text{Actual yield}}{\text{Percent yield}}\times100$.

Step2: Substitute the given values

The actual yield is 12.5 g and the percent yield is 38.5%. So, Theoretical yield=$\frac{12.5}{38.5}\times100$ g.
Theoretical yield = $\frac{1250}{38.5}\approx32.5$ g.

Answer:

32.5g