Question

1. write a skeleton and a balanced chemical equation for each chemical reaction. a-12 - 2 marks for the skeleton equation - 2 marks for the balanced equation a) calcium +potassium chloride → calcium chloride + potassium b) magnesium chloride + sodium nitrate → magnesium nitrate + sodium chloride c) potassium sulfate + lead(ii) nitrate → potassium nitrate + lead(ii) sulfate

Explanation:

Step1: Write skeleton equation for a

Write reactants and products as - is.
$Ca + KCl
ightarrow CaCl_2+K$

Step2: Balance equation for a

Balance Cl atoms first, then others.
$Ca + 2KCl
ightarrow CaCl_2+2K$

Step3: Write skeleton equation for b

Write reactants and products as - is.
$MgCl_2 + NaNO_3
ightarrow Mg(NO_3)_2+NaCl$

Step4: Balance equation for b

Balance Cl and NO₃⁻ groups.
$MgCl_2 + 2NaNO_3
ightarrow Mg(NO_3)_2+2NaCl$

Step5: Write skeleton equation for c

Write reactants and products as - is.
$K_2SO_4 + Pb(NO_3)_2
ightarrow KNO_3+PbSO_4$

Step6: Balance equation for c

Balance K and NO₃⁻ groups.
$K_2SO_4 + Pb(NO_3)_2
ightarrow 2KNO_3+PbSO_4$

Answer:

a) Skeleton: $Ca + KCl
ightarrow CaCl_2+K$; Balanced: $Ca + 2KCl
ightarrow CaCl_2+2K$
b) Skeleton: $MgCl_2 + NaNO_3
ightarrow Mg(NO_3)_2+NaCl$; Balanced: $MgCl_2 + 2NaNO_3
ightarrow Mg(NO_3)_2+2NaCl$
c) Skeleton: $K_2SO_4 + Pb(NO_3)_2
ightarrow KNO_3+PbSO_4$; Balanced: $K_2SO_4 + Pb(NO_3)_2
ightarrow 2KNO_3+PbSO_4$