Question

2.08 - solve linear equations with fractions
due sunday by 11:59pm points 100 submitting an external tool
question
solve: $\frac{2c - 5}{-3}=\frac{2c}{3}$
provide your answer below:
c = □

Explanation:

Step1: Cross - multiply

Multiply both sides by - 3 and 3 to get rid of denominators.
$3(2c - 5)=-3\times2c$

Step2: Expand the left - hand side

Use the distributive property $a(b - c)=ab - ac$.
$6c-15=-6c$

Step3: Add 6c to both sides

To get all c terms on one side.
$6c + 6c-15=-6c+6c$
$12c-15 = 0$

Step4: Add 15 to both sides

Isolate the term with c.
$12c-15 + 15=0 + 15$
$12c=15$

Step5: Divide both sides by 12

Solve for c.
$c=\frac{15}{12}=\frac{5}{4}$

Answer:

$c=\frac{5}{4}$