Question

1. -10.7 points use sigma notation to write the sum. \\( \frac{8}{3 + 1} + \frac{8}{3 + 2} + \frac{8}{3 + 3} + \dots + \frac{8}{3 + 11} \\) \\( \sum_{i = 1}^{\square} \square \\) resources read it ebook use of cookies we and our partners may use cookies, pixels, and similar technologies to collect information about you, including about your browsing activities and devices. this may result in your information being collected by our third - party partners. by choosing to \accept all cookies\, you agree to these practices, including as described in the privacy policy

Explanation:

Step1: Identify the general term

Observe the pattern: each term has numerator 8, denominator $3+i$, where $i$ starts at 1 and ends at 11.
General term: $\frac{8}{3+i}$

Step2: Set sigma bounds

The index $i$ runs from 1 to 11, so we define the sum with these limits.

Answer:

$\sum_{i=1}^{11} \frac{8}{3+i}$