Question

1. 13, 19, 17, 10, 22, 14, 17

mean =
median =
mode =
range =
outlier =

1. 85, 75, 90, 60, 80

mean =
median =
mode =
range =
outlier =

1. 48, 64, 80, 48

mean =
median =
mode =
range =
outlier =

1. 119, 140, 119, 91, 91, 126, 91

mean =
median =
mode =
range =
outlier =

1. 1, 1, 7, 5, 3, 9, 10

mean =
median =
mode =
range =
outlier =

Explanation:

Problem 6: Data set - 13, 19, 17, 10, 72, 14, 17

Mean

Step1: Sum the data values

Sum = \( 13 + 19 + 17 + 10 + 72 + 14 + 17 \) = \( 162 \)

Step2: Divide by the number of values (n = 7)

Mean = \( \frac{162}{7} \approx 23.14 \)

Median

Step1: Order the data: 10, 13, 14, 17, 17, 19, 72

Step2: Find the middle value (n = 7, middle index = 3 (0 - based) or 4 (1 - based))

Median = \( 17 \)

Mode

Step1: Identify the most frequent value

17 appears twice, others once.
Mode = \( 17 \)

Range

Answer:

Step1: No value is extremely far from the others.

Outlier = None

Final Answers (Summarized)

1. Mean: \( \approx 23.14 \), Median: \( 17 \), Mode: \( 17 \), Range: \( 62 \), Outlier: \( 72 \)
2. Mean: \( 78 \), Median: \( 80 \), Mode: No mode, Range: \( 30 \), Outlier: None
3. Mean: \( 60 \), Median: \( 56 \), Mode: \( 48 \), Range: \( 32 \), Outlier: None
4. Mean: \( 111 \), Median: \( 119 \), Mode: \( 91 \), Range: \( 49 \), Outlier: None
5. Mean: \( \approx 5.14 \), Median: \( 5 \), Mode: \( 1 \), Range: \( 9 \), Outlier: None