Question

1. the length of a virus particle is 3.0×10^(-8) meters, and the length of a bacteria cell is 4.3×10^(-6). how many times bigger is the bacteria? o 6.98×10^(-1) times o 1.43×10^2 times o 1.43×10^1 times o 1.43×10^3 times

Explanation:

Step1: Set up the division

To find out how many times bigger the bacteria cell is than the virus particle, we divide the length of the bacteria cell by the length of the virus particle. The length of the bacteria cell is $4.3\times10^{- 6}$ meters and the length of the virus particle is $3.0\times10^{-8}$ meters. So the calculation is $\frac{4.3\times10^{-6}}{3.0\times10^{-8}}$.

Step2: Use the rule of exponents for division

When dividing numbers in scientific - notation $a\times10^{m}$ by $b\times10^{n}$, we use the rule $\frac{a\times10^{m}}{b\times10^{n}}=\frac{a}{b}\times10^{m - n}$. Here, $a = 4.3$, $b = 3.0$, $m=-6$ and $n = - 8$. First, $\frac{4.3}{3.0}\approx1.43$, and $m - n=-6-(-8)=-6 + 8 = 2$. So the result is $1.43\times10^{2}$.

Answer:

$1.43\times10^{2}$ times