Question

q 25.) a spinner has 4 equal sections; red, green, blue and orange. ricardo is going to spin the spinner twice. he uses the chart below to help him determine the probability of an event. what is the probability that the spinner will land on a green section at least once? express your answer as a fraction in simplest form.
1st spin 2nd spin outcomes
red red red, red
red green red, green
red blue red, blue
red orange red, orange
green red green, red
green green green, green
green blue green, blue
green orange green, orange
blue red blue, red
blue green blue, green
blue blue blue, blue
blue orange blue, orange
orange red orange, red
orange green orange, green
orange blue orange, blue
orange orange orange, orange
answer________

Explanation:

Step1: Find the probability of not landing on green in one spin

The probability of not landing on green in one spin is $\frac{3}{4}$ since there are 3 non - green sections out of 4 total sections.

Step2: Find the probability of not landing on green in two spins

Since the spins are independent events, the probability of not landing on green in two spins is $\frac{3}{4}\times\frac{3}{4}=\frac{9}{16}$.

Step3: Find the probability of landing on green at least once

The probability of landing on green at least once is the complement of the probability of not landing on green in two spins. So it is $1-\frac{9}{16}=\frac{16 - 9}{16}=\frac{7}{16}$.

Answer:

$\frac{7}{16}$