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2a) the table shows the distance penelope is from the park as she walks…

Question

2a) the table shows the distance penelope is from the park as she walks to soccer practice. assume the relationship between the two quantities is linear. \

$$\begin{tabular}{|c|c|} \\hline time (min), $x$ & distance (m), $y$ \\\\ \\hline 5 & 1,930 \\\\ \\hline 10 & 1,380 \\\\ \\hline 15 & 830 \\\\ \\hline 20 & 280 \\\\ \\hline \\end{tabular}$$

find and interpret the rate of change. the rate of change is \underline{\qquad}, so penelope is \underline{\qquad} meters closer to the park every minute. find and interpret the initial value. the initial value is \underline{\qquad}, so penelope was initially \underline{\qquad} meters from the park. 2b) write the equation in the form $y = mx + b$.

Explanation:

Response
2A) Rate of Change

Step1: Recall rate of change formula

The rate of change (slope) \( m \) for a linear relationship is given by \( m=\frac{y_2 - y_1}{x_2 - x_1} \). Let's take two points, say \( (x_1,y_1)=(5,1930) \) and \( (x_2,y_2)=(10,1380) \).

Step2: Calculate the rate of change

Substitute into the formula: \( m=\frac{1380 - 1930}{10 - 5}=\frac{- 550}{5}=- 110 \).
Interpretation: The negative sign indicates the distance from the park is decreasing. So Penelope is 110 meters closer to the park every minute.

2A) Initial Value

Step1: Use the linear equation \( y = mx + b \)

We know \( m=-110 \), and we can use a point, e.g., \( (5,1930) \). Substitute into \( y = mx + b \): \( 1930=-110(5)+b \).

Step2: Solve for \( b \)

Calculate \( -110(5)=-550 \), then \( 1930=-550 + b \). Add 550 to both sides: \( b = 1930 + 550 = 2480 \).
Interpretation: The initial value \( b \) is the distance from the park when time \( x = 0 \) (initial time), so Penelope was initially 2480 meters from the park.

2B) Equation

Step1: Identify \( m \) and \( b \)

From 2A, \( m=-110 \) and \( b = 2480 \).

Step2: Write the equation

Using \( y=mx + b \), substitute \( m \) and \( b \): \( y=-110x + 2480 \).

Answer:

s:
2A) The rate of change is \(-110\), so Penelope is \(110\) meters closer to the park every minute.
The initial value is \(2480\), so Penelope was initially \(2480\) meters from the park.
2B) The equation is \( y=-110x + 2480 \).