Question

1. jeffrey is looking at a map of his town to help him get from his school to the library. if 1 inch is equal to 9 miles, and the distance on the map is $\frac{1}{4}$ inch, how far is it to the library?

2.25 miles
9 miles
4.5 miles
36 miles

1. joyanna is 14 years old. how many minutes is this? (three of these years were leap years.)

7, 358, 400 minutes
126, 960 minutes
18, 396, 000 minutes
7, 362, 720 minutes

Explanation:

Question 49

Step1: Identify the scale

The scale is 1 inch = 9 miles. The map distance is $\frac{1}{4}$ inch.

Step2: Calculate the actual distance

To find the actual distance, multiply the map distance by the scale factor. So, the actual distance $d = \frac{1}{4} \times 9$ miles.
Calculating $\frac{1}{4} \times 9 = \frac{9}{4} = 2.25$ miles.

Step1: Determine the number of days

A non - leap year has 365 days and a leap year has 366 days. Joyanna is 14 years old with 3 leap years. So, the number of non - leap years is $14 - 3=11$.
The total number of days $D=11\times365 + 3\times366$.
Calculating $11\times365 = 4015$ and $3\times366 = 1098$. Then $D = 4015+1098 = 5113$ days.

Step2: Convert days to minutes

We know that 1 day has 24 hours and 1 hour has 60 minutes. So, 1 day has $24\times60 = 1440$ minutes.
To find the total number of minutes, multiply the number of days by 1440. So, the total number of minutes $M = 5113\times1440$.
Calculating $5113\times1440=(5000 + 113)\times1440=5000\times1440+113\times1440$.
$5000\times1440 = 7200000$ and $113\times1440=(100 + 13)\times1440=100\times1440+13\times1440 = 144000+18720 = 162720$.
Then $M=7200000 + 162720=7362720$ minutes.

Answer:

2.25 miles

Question 50