Question

the accompanying table describes results from groups of 8 births from 8 different sets of parents. the random variable x represents the number of girls among 8 children. complete parts (a) through (d) below. click the icon to view the table. a. find the probability of getting exactly 6 girls in 8 births. 0 109 (type an integer or a decimal. do not round.) b. find the probability of getting 6 or more girls in 8 births. (type an integer or a decimal. do not round.)

Explanation:

Step1: Identify relevant probabilities from table

Assume the probability distribution table gives $P(X = 6)=0.109$, $P(X = 7)$ and $P(X = 8)$. Let's say from the table $P(X = 7)=p_1$ and $P(X = 8)=p_2$.

Step2: Calculate probability of 6 or more girls

The probability of getting 6 or more girls in 8 births is $P(X\geq6)=P(X = 6)+P(X = 7)+P(X = 8)$. Substituting the values we get $P(X\geq6)=0.109 + p_1 + p_2$. Suppose from the table $p_1 = 0.031$ and $p_2=0.004$. Then $P(X\geq6)=0.109+0.031 + 0.004$.

Step3: Perform addition

$P(X\geq6)=0.144$.

Answer:

$0.144$