Question

the actual weight of a bag of rice is 30 ounces, but the listed weight is 21 ounces. what percent is the measurement error of the actual weight?
finish labeling the double number line with the measurement error and percent error to represent this problem. let k represent the percent error.

Explanation:

Step1: Calculate measurement error

$21 - 30 = -9$ ounces (negative since listed < actual)

Step2: Calculate percent error $k$

$k = \frac{|\text{error}|}{\text{actual weight}} \times 100\% = \frac{9}{30} \times 100\% = 30\%$

Step3: Match values to number line

The blue box (ounces line) gets the measurement error: $-9$ (or 9, as magnitude, but the value is 9 from options). The empty box (percent line) gets $k = 30\%$.

Answer:

Blue box (ounces line): 9
Empty box (percent line): 30