Question

algebra i with probability young ic qtr a continuous learning center - credit bearing (tutor) solving linear equations: variable on one side two functions are defined as shown. $f(x)=-\frac{1}{2}x - 2$ $g(x)=-1$ which graph shows the input value for which $f(x)=g(x)$?

Explanation:

Step1: Set the functions equal

Set $f(x)=g(x)$, so $-\frac{1}{2}x - 2=-1$.

Step2: Solve for x

Add 2 to both sides: $-\frac{1}{2}x=-1 + 2=1$. Then multiply both sides by - 2, we get $x=-2$.
The graph where the line $y = f(x)=-\frac{1}{2}x - 2$ intersects the horizontal line $y = g(x)=-1$ at $x = - 2$ is the correct one. In a graph, the intersection of $y=-\frac{1}{2}x - 2$ and $y = - 1$ occurs when the x - coordinate of the intersection point is - 2.

Answer:

The graph where the line $y =-\frac{1}{2}x - 2$ and $y=-1$ intersect at $x=-2$ (the first graph as the intersection point of the two lines has x - value of - 2).