Question

algebra i with probability young ic qtr a continuous learning center - credit bearing (tutor) solving linear equations: variable on one side creating a one - variable equation to model and solve a problem this week, michael collected $468 for delivering newspapers. he had 40 repeat customers and 18 new ones. as an incentive, he charged the new subscribers $3 less than the repeat customers. if $x$ represents the amount michael collects from each repeat customer, which equation models this problem? what is the fee michael charges each new subscriber?

Explanation:

Step1: Find amount from repeat - customers

The number of repeat customers is 40 and the amount collected from each repeat customer is $x$. So the total amount collected from repeat customers is $40x$.

Step2: Find amount from new - customers

The amount collected from each new subscriber is $x - 3$. The number of new subscribers is 18. So the total amount collected from new subscribers is $18(x - 3)$.

Step3: Set up the equation

The total amount collected is $468$. So the equation is $40x+18(x - 3)=468$.

Step4: Solve for the fee of new subscribers

First, expand the equation: $40x+18x-54 = 468$. Combine like - terms: $58x=468 + 54=522$. Then $x=\frac{522}{58}=9$. The fee for each new subscriber is $x - 3=9 - 3 = 6$.

Answer:

The equation is $40x+18(x - 3)=468$. The fee Michael charges each new subscriber is $\$6$.