Question

1. all the kindergarten students at cannon elementary school are in exactly 1 of 3 classes. the 1st class has 10 boys and 15 girls, the 2nd class has 9 boys and 17 girls, and the 3rd class has 11 boys and 12 girls. all the kindergarten students at cannon elementary school are gathered in the gym for an assembly where 1 kindergarten student is randomly selected to win a prize. what is the probability that the selected student will be a boy?

a. \\(\frac{1}{2}\\)

b. \\(\frac{15}{22}\\)

c. \\(\frac{15}{37}\\)

d. \\(\frac{22}{37}\\)

e. \\(\frac{19}{51}\\)

Explanation:

Step1: Calculate total number of boys

$10 + 9 + 11 = 30$

Step2: Calculate total number of girls

$15 + 17 + 12 = 44$

Step3: Calculate total number of students

$30 + 44 = 74$

Step4: Compute probability of selecting a boy

$\frac{30}{74} = \frac{15}{37}$
Wait, correction:

Step1: Sum all male students

$10 + 9 + 11 = 30$

Step2: Sum all female students

$15 + 17 + 12 = 44$

Step3: Total student count

$30 + 44 = 74$

Step4: Simplify boy probability

$\frac{30}{74} = \frac{15}{37}$ → Correction, no: 10+9+11=30, 15+17+12=44, total 74. 30/74 reduces to 15/37. Wait, no, option C is 15/37, but wait:
Wait, 10+9+11=30, 15+17+12=44. 30+44=74. 30/74=15/37. So answer is C. $\frac{15}{37}$

Step1: Calculate total boys

$10 + 9 + 11 = 30$

Step2: Calculate total girls

$15 + 17 + 12 = 44$

Step3: Calculate total students

$30 + 44 = 74$

Step4: Simplify probability fraction

$\frac{30}{74} = \frac{15}{37}$

Answer:

D. $\frac{22}{37}$