Question

answer the following questions using the hardy - weinberg equation. be sure to express the relative frequencies as decimals (i.e., 0.16) and percentages as percentages (i.e., 16%).

1. you have sampled a population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. using that 36%, calculate the following:

a. the frequency of the \a\ allele: ______
b. the frequency of the \a\ allele: ______
c. the frequency of the \aa\ genotype: ______
d. the frequency of the \aa\ genotype: ______
e. the frequency of the \aa\ genotype: ______

Explanation:

Step1: Calculate frequency of "a" allele

Given that the frequency of the homozygous recessive genotype ($aa$) is $q^{2}=0.36$. Taking the square - root of $q^{2}$ to find the frequency of the "a" allele ($q$).
$q = \sqrt{0.36}=0.6$

Step2: Calculate frequency of "A" allele

Using the Hardy - Weinberg equation $p + q=1$, where $p$ is the frequency of the "A" allele and $q$ is the frequency of the "a" allele.
$p=1 - q=1 - 0.6 = 0.4$

Step3: Calculate frequency of "AA" genotype

The frequency of the homozygous dominant genotype ($AA$) is $p^{2}$.
$p^{2}=(0.4)^{2}=0.16$

Step4: Calculate frequency of "Aa" genotype

The frequency of the heterozygous genotype ($Aa$) is $2pq$.
$2pq = 2\times0.4\times0.6=0.48$

Step5: Frequency of "aa" genotype is already given

The frequency of the homozygous recessive genotype ($aa$) is $q^{2}=0.36$

Answer:

a. $0.4$
b. $0.6$
c. $0.16$
d. $0.48$
e. $0.36$