Question

assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75 probability that a pea has green pods. assume that the offspring peas are randomly selected in groups of 18. complete parts (a) through (c) below.
a. find the mean and the standard deviation for the numbers of peas with green pods in the groups of 18.
the value of the mean is μ = peas.
(type an integer or a decimal. do not round.)

Explanation:

Step1: Identify the distribution

This is a binomial distribution problem. Here, $n = 18$ (number of trials/sample size) and $p=0.75$ (probability of success).

Step2: Apply the mean formula for binomial distribution

The mean formula for a binomial distribution is $\mu = np$. Substituting $n = 18$ and $p = 0.75$ into the formula, we get $\mu=18\times0.75$.

Step3: Calculate the mean

$18\times0.75 = 13.5$.

Answer:

13.5