Question

a bag contains only yellow marbles and red marbles. the probability of selecting a yellow marble from the bag at random is $\frac{3}{14}$. what is the probability of selecting a red marble from the bag at random?

Explanation:

Step1: Recall probability rule

The sum of probabilities of all possible outcomes is 1. Here the possible outcomes are selecting a yellow marble or a red marble.

Step2: Let probabilities

Let $P(Y)$ be the probability of selecting a yellow marble and $P(R)$ be the probability of selecting a red marble. We know $P(Y)+P(R) = 1$. Given $P(Y)=\frac{3}{14}$.

Step3: Calculate $P(R)$

$P(R)=1 - P(Y)=1-\frac{3}{14}=\frac{14 - 3}{14}=\frac{11}{14}$

Answer:

$\frac{11}{14}$