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a bag contains 1 red tile, 1 blue tile, 1 green tile, 1 yellow tile, an…

Question

a bag contains 1 red tile, 1 blue tile, 1 green tile, 1 yellow tile, and 1 purple tile. kaison chooses a tile from the bag, records its color, and then replaces the tile. she repeats this procedure a total of 50 times. her results are shown in the table. table columns: color (red, blue, green, yellow, purple); observed frequency (15, 12, 8, 10, 5); relative frequency (\\(\frac{3}{10}\\), \\(\frac{6}{25}\\), \\(\frac{4}{25}\\), \\(\frac{1}{5}\\), \\(\frac{1}{10}\\))

Explanation:

Response

Assuming the question is to verify the relative frequencies or find the total number of trials (which is 50, as 15 + 12 + 8 + 10 + 5 = 50), or check if relative frequencies are calculated correctly (e.g., for Red: 15/50 = 3/10, Blue: 12/50 = 6/25, Green: 8/50 = 4/25, Yellow: 10/50 = 1/5, Purple: 5/50 = 1/10, all correct). Here's a step - by - step for verifying total trials:

Step1: Sum the frequencies

We need to add up the observed frequencies for each color. The frequencies are 15 (Red), 12 (Blue), 8 (Green), 10 (Yellow), and 5 (Purple).
The sum is calculated as $15 + 12+8 + 10+5$.

Step2: Calculate the sum

First, $15+12 = 27$. Then, $27 + 8=35$. Next, $35 + 10 = 45$. Finally, $45+5 = 50$.

Answer:

50