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7. based on the information in this table, which man could not be the f…

Question

  1. based on the information in this table, which man could not be the father of the baby? justify your answer with a punnett square.
nameblood type--------mothertype ababytype bsammy the playertype ogeorge the sleezetype abthe waitertype athe cable guytype b8. based on the information in this table, which man could not be the father of the baby? justify your answer with a punnett square.
nameblood type--------mothertype obabytype abbartendertype oguy at the clubtype abcabdrivertype aflight attendanttype b9. explain why blood type data cannot prove who the father of a baby is, and can only prove who the father is not.

Explanation:

Response
Question 7

Step1: Define blood type genotypes

Blood type A can be $I^A I^A$ or $I^A i$; type B is $I^B I^B$ or $I^B i$; type O is $ii$; type AB is $I^A I^B$. Baby is type B, so genotype is $I^B I^B$ or $I^B i$. Mother is type A, so she can only pass $I^A$ or $i$. For baby to be B, mother must pass $i$, so baby's genotype is $I^B i$ (father must pass $I^B$).

Step2: Test Sammy (type O, $ii$)

Punnett square for mother ($I^A i$) and Sammy ($ii$):

$$\begin{array}{c|cc} & I^A & i \\ \hline i & I^A i & ii \\ i & I^A i & ii \\ \end{array}$$

Offspring can only be type A ($I^A i$) or O ($ii$), no type B.

Step3: Test other men

  • George (AB, $I^A I^B$): Can pass $I^B$, so baby can be $I^B i$ (type B).
  • Waiter (A, $I^A i$): If mother is $I^A i$, waiter cannot pass $I^B$, but wait no—wait, mother is A, baby is B, so father must have $I^B$. Waiter (A) has no $I^B$, but wait no: Wait, mother is A, to get baby B, father must contribute $I^B$. Waiter is A, so no $I^B$, but wait Sammy is O, also no $I^B$. Wait no, step 2: Sammy can only pass $i$, so baby can't get $I^B$. Waiter could be $I^A I^A$ or $I^A i$, but no $I^B$, so baby can't be B. Wait no, wait the baby is B, so must get $I^B$ from father. So Sammy (O, $ii$) can't give $I^B$, so no type B baby.

Step1: Define blood type genotypes

Mother is type O, so genotype $ii$; baby is type AB, genotype $I^A I^B$.

Step2: Test Bartender (type O, $ii$)

Punnett square for mother ($ii$) and Bartender ($ii$):

$$\begin{array}{c|cc} & i & i \\ \hline i & ii & ii \\ i & ii & ii \\ \end{array}$$

Offspring can only be type O ($ii$), no AB.

Step3: Test other men

  • Guy at club (AB, $I^A I^B$): Can pass $I^A$ or $I^B$, mother passes $i$? No, baby is AB, so needs $I^A$ and $I^B$. Wait mother is $ii$, can only pass $i$, so baby can't get $I^A$ or $I^B$ from mother. Wait wait, baby is AB, so must get $I^A$ from one parent and $I^B$ from the other. Mother is O ($ii$), can't pass $I^A$ or $I^B$, so baby can't be AB? No, wait the question says baby is AB, so father must provide both $I^A$ and $I^B$? No, no: each parent passes one allele. So baby AB needs $I^A$ from one parent, $I^B$ from the other. Mother is O, can't pass either, so wait no—wait the question says "which man could not be the father". Wait Bartender is O, so can't pass $I^A$ or $I^B$, so baby can't be AB. The other men: Guy at club (AB) can pass $I^A$ or $I^B$, but mother can only pass $i$, so baby would be $I^A i$ (A) or $I^B i$ (B), not AB. Wait no, wait this is a mistake. Wait the baby is AB, so requires one parent to pass $I^A$ and the other to pass $I^B$. Mother is O ($ii$), can't pass either, so none of the men can be father? No, the question says "which man could not be the father"—wait no, the Bartender is O, so definitely can't, but the others also can't? No, wait no, maybe I messed up. Wait no, the question says "which man could not be the father"—the Bartender (type O) is the one that is impossible, because even if other men can't produce AB, the Bartender is the most impossible? Wait no, the Punnett square for mother O and Bartender O only produces O, so baby can't be AB.
Brief Explanations

Blood type inheritance only rules out impossible fathers by showing that a man's genotype cannot produce the baby's blood type. However, multiple men can have blood types that are genetically compatible with producing the baby's blood type, since blood type is a trait with limited, shared genetic possibilities. There is no unique genetic marker in blood types that can definitively confirm paternity, only eliminate those who cannot contribute the necessary alleles.

Answer:

Sammy the player could not be the father. The Punnett square shows that a type A mother (genotype $I^A i$) and type O father (genotype $ii$) can only have offspring with type A ($I^A i$) or type O ($ii$) blood, which cannot produce a type B baby.

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Question 8